C++ Code Of If else Statements 1

Find the absolute value of a number entered by the user.

#include<iostream.h>
#include<conio.h>


int main()
{
 int a;
 cout<<"Enter any number:";
 cin>>a;

 if(a>0)
  cout<<"The absolute value of number is:"<<a;
 else
  cout<<"The absolute value of number is:"<<-(a);

 getch();
 return 0;
}

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Write a program to calculate the monthly telephone bills as per the following rule:
Minimum Rs. 200 for upto 100 calls.
Plus Rs. 0.60 per call for next 50 calls.
Plus Rs. 0.50 per call for next 50 calls.
Plus Rs. 0.40 per call for any call beyond 200 calls.

#include<iostream.h>
#include<conio.h>

int main()
{
 int calls;
 float bill;
 cout<<"Enter number of calls : ";
 cin>>calls;

 if(calls<=100)
  bill=200;
 else if (calls>100 && calls<=150)
   {
       calls=calls-100;
       bill=200+(0.60*calls);
 }
 else if (calls>150 && calls<=200)
 {
  calls=calls-150;
  bill=200+(0.60*50)+(0.50*calls);
  }
 else
 {
  calls=calls-200;
  bill=200+(0.60*50)+(0.50*50)+(0.40*calls);
 }

 cout<<" Your bill is Rs."<<bill;

 getch();
 return 0;
}

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Write a program to find the roots of a quadratic equation of type ax2+bx+c where a is not equal to zero.

#include<iostream.h>
#include<conio.h>
#include<math.h>


int main()
{
 float a,b,c,d,root1,root2;
 cout<<"Enter value of  a, b and c : ";
 cin>>a>>b>>c;

 d=b*b-4*a*c;

 if(d==0)
 {
  root1=(-b)/(2*a);
  root2=root1;
  cout<<"Roots are real & equal";
   }
 else if(d>0)
 {
  root1=-(b+sqrt(d))/(2*a);
  root2=-(b-sqrt(d))/(2*a);
  cout<<"Roots are real & distinct";
 }
 else
 {
  root1=(-b)/(2*a);
  root2=sqrt(-d)/(2*a);
  cout<<"Roots are imaginary";
 }

 cout<<"\nRoot 1= "<<root1<<"\nRoot 2= "<<root2;

 getch();
 return 0;
}